What can be determined from the meter, except for electricity consumption

First, it is possible to determine whether there are currently any lamps or electrical appliances turned on somewhere in the apartment. If the counter is spinning, it means they are available. If it's still, it's all off.

Second, what power are the devices now on. Using the second clockwise we determine how long it takes the disk to complete, for example 40 revolutions. This is easy to do as there is a blackened bar on the disc which is clearly visible in the window when the disc completes one spin and starts the next. Let's say 75 seconds are spent on 40 revolutions. Then we read on the counter, for example, "1 kWh — 5000 revolutions" and make up the proportion, based on the following.

If at 1 kWh = 1000 x 3600 = 3600000 watt-seconds (W-s), 5000 revolutions and with X W -s — 40 revolutions, then X = 3 600 000 x 40: 5000 = 28 800 Avg. S.

Knowing that 28,800 watts are consumed in 75 seconds, it is not difficult to determine the power of the appliances involved. For this, 28,800: 75 = 384 watts are enough.

Third, what current flows through the meter. By dividing the power just defined by the nominal line voltage, we get 384 W: 127 V = 3 A (or 384: 220 -1.74 A).

Fourth, you can tell from the counter if the network is congested. Knowing what cross-section the wires coming from the meter have, it is easy to determine the long-term permissible current through them, for example 20 A. Multiplying this current by the nominal voltage of the network, find out what power it corresponds to. In this example it is 20 A — 127 'B = 2540 W (or 20 A x 220 V = 4400 W). We ask for some period of time, for example 30 s, and by multiplying 2540 and 30, we find that the meter should count 2540 x 30 = 76,200 watt-s. Let the meter read "1 kWh — 5000 revolutions".

Therefore, at 1 kWh = 3,600,000 Watt-s, 5,000 revolutions occur, and at 76,200 W / s, 76,200 x 5,000: 3,600,000 = 106 revolutions must occur. Thus, if the wires are not overloaded, then the counter makes no more than 106 revolutions in half a minute.

Fifth, is it possible to determine if the counter itself is overloaded? Leave it written «5-15 A, 220 V, 1 kWh = 1250 revolutions.» Maximum current correspond to power 15 x 220 = 3300 W. power consumption for 30 s 3300 x 30 = 99,000 W / s and 99,000 — 1,250: 3,600,000 = 34 revolutions of the disk. Therefore, if in 30 s the disc will make no more than 34 revolutions, then the counter is not overloaded.

Sixth, you can calculate how much electricity is used for the total area of ​​the total apartment? Let's say that in a large apartment there are two meters, the load between which is distributed approximately equally. Additionally, each of the five families has control gauges.One total meter per month counted 125, another 95 kWh.

This means that 125 + 95 = 220 kWh were used in total. And control counters taken into account 40 + 51 +44 + 27 + 31 = 193 kWh. from which it follows that the total area consumed 220 — 193 = 27 kWh.

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